> From: Keith Marshall <keith****@users*****> > Date: Tue, 12 Mar 2019 22:06:06 +0000 > > On 12/03/19 15:41, Eli Zaretskii wrote: > > Does anyone know what happens if a program is compiled that uses this > > class? Will it fail to compile, or abort at run time, or something > > else? > > I reviewed some of our historical archives, (my own local copies); it > appears that, if GCC has been built with the win32 thread model, the > class definition isn't exposed, so you get a compile time failure, > diagnosed as "thread is not a member of std", or some such. Yes, you are right. For the record: the simple test program below produces the following diagnostics: D:\usr\eli\data>g++ -c ./threaded-hello.cc ./threaded-hello.cc: In function 'int main()': ./threaded-hello.cc:12:8: error: 'thread' is not a member of 'std' std::thread t1(call_from_thread); ^~~~~~ ./threaded-hello.cc:12:8: note: suggested alternative: 'tera' std::thread t1(call_from_thread); ^~~~~~ tera ./threaded-hello.cc:15:3: error: 't1' was not declared in this scope t1.join(); ^~ ./threaded-hello.cc:15:3: note: suggested alternative: 'tm' t1.join(); ^~ tm Here's source code of the program I used: #include <iostream> #include <thread> //This function will be called from a thread void call_from_thread() { std::cout << "Hello, World" << std::endl; } int main() { //Launch a thread std::thread t1(call_from_thread); //Join the thread with the main thread t1.join(); return 0; }
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